3.16.64 \(\int \frac {(d+e x)^4}{(a d e+(c d^2+a e^2) x+c d e x^2)^2} \, dx\)

Optimal. Leaf size=74 \[ -\frac {\left (c d^2-a e^2\right )^2}{c^3 d^3 (a e+c d x)}+\frac {2 e \left (c d^2-a e^2\right ) \log (a e+c d x)}{c^3 d^3}+\frac {e^2 x}{c^2 d^2} \]

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Rubi [A]  time = 0.06, antiderivative size = 74, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.057, Rules used = {626, 43} \begin {gather*} -\frac {\left (c d^2-a e^2\right )^2}{c^3 d^3 (a e+c d x)}+\frac {2 e \left (c d^2-a e^2\right ) \log (a e+c d x)}{c^3 d^3}+\frac {e^2 x}{c^2 d^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(d + e*x)^4/(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^2,x]

[Out]

(e^2*x)/(c^2*d^2) - (c*d^2 - a*e^2)^2/(c^3*d^3*(a*e + c*d*x)) + (2*e*(c*d^2 - a*e^2)*Log[a*e + c*d*x])/(c^3*d^
3)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 626

Int[((d_) + (e_.)*(x_))^(m_.)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[(d + e*x)^(m + p)*(a
/d + (c*x)/e)^p, x] /; FreeQ[{a, b, c, d, e, m}, x] && NeQ[b^2 - 4*a*c, 0] && EqQ[c*d^2 - b*d*e + a*e^2, 0] &&
IntegerQ[p]

Rubi steps

\begin {align*} \int \frac {(d+e x)^4}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^2} \, dx &=\int \frac {(d+e x)^2}{(a e+c d x)^2} \, dx\\ &=\int \left (\frac {e^2}{c^2 d^2}+\frac {\left (c d^2-a e^2\right )^2}{c^2 d^2 (a e+c d x)^2}+\frac {2 \left (c d^2 e-a e^3\right )}{c^2 d^2 (a e+c d x)}\right ) \, dx\\ &=\frac {e^2 x}{c^2 d^2}-\frac {\left (c d^2-a e^2\right )^2}{c^3 d^3 (a e+c d x)}+\frac {2 e \left (c d^2-a e^2\right ) \log (a e+c d x)}{c^3 d^3}\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 65, normalized size = 0.88 \begin {gather*} \frac {2 \left (c d^2 e-a e^3\right ) \log (a e+c d x)-\frac {\left (c d^2-a e^2\right )^2}{a e+c d x}+c d e^2 x}{c^3 d^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(d + e*x)^4/(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^2,x]

[Out]

(c*d*e^2*x - (c*d^2 - a*e^2)^2/(a*e + c*d*x) + 2*(c*d^2*e - a*e^3)*Log[a*e + c*d*x])/(c^3*d^3)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(d+e x)^4}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(d + e*x)^4/(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^2,x]

[Out]

IntegrateAlgebraic[(d + e*x)^4/(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^2, x]

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fricas [A]  time = 0.40, size = 117, normalized size = 1.58 \begin {gather*} \frac {c^{2} d^{2} e^{2} x^{2} + a c d e^{3} x - c^{2} d^{4} + 2 \, a c d^{2} e^{2} - a^{2} e^{4} + 2 \, {\left (a c d^{2} e^{2} - a^{2} e^{4} + {\left (c^{2} d^{3} e - a c d e^{3}\right )} x\right )} \log \left (c d x + a e\right )}{c^{4} d^{4} x + a c^{3} d^{3} e} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^4/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^2,x, algorithm="fricas")

[Out]

(c^2*d^2*e^2*x^2 + a*c*d*e^3*x - c^2*d^4 + 2*a*c*d^2*e^2 - a^2*e^4 + 2*(a*c*d^2*e^2 - a^2*e^4 + (c^2*d^3*e - a
*c*d*e^3)*x)*log(c*d*x + a*e))/(c^4*d^4*x + a*c^3*d^3*e)

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giac [B]  time = 0.20, size = 389, normalized size = 5.26 \begin {gather*} \frac {2 \, {\left (c^{4} d^{8} e - 4 \, a c^{3} d^{6} e^{3} + 6 \, a^{2} c^{2} d^{4} e^{5} - 4 \, a^{3} c d^{2} e^{7} + a^{4} e^{9}\right )} \arctan \left (\frac {2 \, c d x e + c d^{2} + a e^{2}}{\sqrt {-c^{2} d^{4} + 2 \, a c d^{2} e^{2} - a^{2} e^{4}}}\right )}{{\left (c^{5} d^{7} - 2 \, a c^{4} d^{5} e^{2} + a^{2} c^{3} d^{3} e^{4}\right )} \sqrt {-c^{2} d^{4} + 2 \, a c d^{2} e^{2} - a^{2} e^{4}}} + \frac {x e^{2}}{c^{2} d^{2}} + \frac {{\left (c d^{2} e - a e^{3}\right )} \log \left (c d x^{2} e + c d^{2} x + a x e^{2} + a d e\right )}{c^{3} d^{3}} - \frac {\frac {c^{4} d^{8} - 4 \, a c^{3} d^{6} e^{2} + 6 \, a^{2} c^{2} d^{4} e^{4} - 4 \, a^{3} c d^{2} e^{6} + a^{4} e^{8}}{c} + \frac {{\left (c^{4} d^{8} e - 4 \, a c^{3} d^{6} e^{3} + 6 \, a^{2} c^{2} d^{4} e^{5} - 4 \, a^{3} c d^{2} e^{7} + a^{4} e^{9}\right )} x}{c d}}{{\left (c^{2} d^{4} - 2 \, a c d^{2} e^{2} + a^{2} e^{4}\right )} {\left (c d x^{2} e + c d^{2} x + a x e^{2} + a d e\right )} c^{2} d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^4/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^2,x, algorithm="giac")

[Out]

2*(c^4*d^8*e - 4*a*c^3*d^6*e^3 + 6*a^2*c^2*d^4*e^5 - 4*a^3*c*d^2*e^7 + a^4*e^9)*arctan((2*c*d*x*e + c*d^2 + a*
e^2)/sqrt(-c^2*d^4 + 2*a*c*d^2*e^2 - a^2*e^4))/((c^5*d^7 - 2*a*c^4*d^5*e^2 + a^2*c^3*d^3*e^4)*sqrt(-c^2*d^4 +
2*a*c*d^2*e^2 - a^2*e^4)) + x*e^2/(c^2*d^2) + (c*d^2*e - a*e^3)*log(c*d*x^2*e + c*d^2*x + a*x*e^2 + a*d*e)/(c^
3*d^3) - ((c^4*d^8 - 4*a*c^3*d^6*e^2 + 6*a^2*c^2*d^4*e^4 - 4*a^3*c*d^2*e^6 + a^4*e^8)/c + (c^4*d^8*e - 4*a*c^3
*d^6*e^3 + 6*a^2*c^2*d^4*e^5 - 4*a^3*c*d^2*e^7 + a^4*e^9)*x/(c*d))/((c^2*d^4 - 2*a*c*d^2*e^2 + a^2*e^4)*(c*d*x
^2*e + c*d^2*x + a*x*e^2 + a*d*e)*c^2*d^2)

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maple [A]  time = 0.06, size = 114, normalized size = 1.54 \begin {gather*} -\frac {a^{2} e^{4}}{\left (c d x +a e \right ) c^{3} d^{3}}+\frac {2 a \,e^{2}}{\left (c d x +a e \right ) c^{2} d}-\frac {d}{\left (c d x +a e \right ) c}-\frac {2 a \,e^{3} \ln \left (c d x +a e \right )}{c^{3} d^{3}}+\frac {2 e \ln \left (c d x +a e \right )}{c^{2} d}+\frac {e^{2} x}{c^{2} d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^4/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^2,x)

[Out]

e^2*x/c^2/d^2-2/d^3/c^3*e^3*ln(c*d*x+a*e)*a+2/d/c^2*e*ln(c*d*x+a*e)-1/c^3/d^3/(c*d*x+a*e)*a^2*e^4+2/c^2/d/(c*d
*x+a*e)*a*e^2-1/c*d/(c*d*x+a*e)

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maxima [A]  time = 1.01, size = 89, normalized size = 1.20 \begin {gather*} -\frac {c^{2} d^{4} - 2 \, a c d^{2} e^{2} + a^{2} e^{4}}{c^{4} d^{4} x + a c^{3} d^{3} e} + \frac {e^{2} x}{c^{2} d^{2}} + \frac {2 \, {\left (c d^{2} e - a e^{3}\right )} \log \left (c d x + a e\right )}{c^{3} d^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^4/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^2,x, algorithm="maxima")

[Out]

-(c^2*d^4 - 2*a*c*d^2*e^2 + a^2*e^4)/(c^4*d^4*x + a*c^3*d^3*e) + e^2*x/(c^2*d^2) + 2*(c*d^2*e - a*e^3)*log(c*d
*x + a*e)/(c^3*d^3)

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mupad [B]  time = 0.62, size = 96, normalized size = 1.30 \begin {gather*} \frac {e^2\,x}{c^2\,d^2}-\frac {\ln \left (a\,e+c\,d\,x\right )\,\left (2\,a\,e^3-2\,c\,d^2\,e\right )}{c^3\,d^3}-\frac {a^2\,e^4-2\,a\,c\,d^2\,e^2+c^2\,d^4}{c\,d\,\left (x\,c^3\,d^3+a\,e\,c^2\,d^2\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d + e*x)^4/(x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^2,x)

[Out]

(e^2*x)/(c^2*d^2) - (log(a*e + c*d*x)*(2*a*e^3 - 2*c*d^2*e))/(c^3*d^3) - (a^2*e^4 + c^2*d^4 - 2*a*c*d^2*e^2)/(
c*d*(c^3*d^3*x + a*c^2*d^2*e))

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sympy [A]  time = 0.44, size = 85, normalized size = 1.15 \begin {gather*} \frac {- a^{2} e^{4} + 2 a c d^{2} e^{2} - c^{2} d^{4}}{a c^{3} d^{3} e + c^{4} d^{4} x} + \frac {e^{2} x}{c^{2} d^{2}} - \frac {2 e \left (a e^{2} - c d^{2}\right ) \log {\left (a e + c d x \right )}}{c^{3} d^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**4/(a*d*e+(a*e**2+c*d**2)*x+c*d*e*x**2)**2,x)

[Out]

(-a**2*e**4 + 2*a*c*d**2*e**2 - c**2*d**4)/(a*c**3*d**3*e + c**4*d**4*x) + e**2*x/(c**2*d**2) - 2*e*(a*e**2 -
c*d**2)*log(a*e + c*d*x)/(c**3*d**3)

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